I had to find all instances of criminals in which both the given-name and surname fields are identical and the number of such duplicates
Here's the SQL I used for the example:
SELECT `surname`, `given_name`, COUNT(`surname`) AS Instances FROM criminals GROUP BY `surname`, `given_name` HAVING ( COUNT(`surname`) > 1 ) AND ( COUNT(`given_name`) > 1)
and here's the same SQL with abstracted table and field names:
SELECT `field1Name`, `field2Name`, COUNT(`field1Name`) AS Instances FROM tableName GROUP BY `field1Name`, `field2Name` HAVING ( COUNT(`field1Name`) > 1 ) AND ( COUNT(`field2Name`) > 1)
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Simon Devereaux has approximately 10,000 records of people convicted in potentially capital cases between 1710 and 1840 in London heard at the Old Bailey court. This project will create a web-based database which will allow interested researchers and members of the public to compose queries on that data (e.g. women charged with robbery 1710-1720). It must be able to support a range of queries and produce output allowing researchers to identify trends in judicial practice over that time.
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